A certain alloy is a mixture of equal number A atoms and B atoms. B atoms are twice as heavy as A atoms. What weight of A atoms is needed to make 600 pounds of the alloy?
Given that number of atoms are equal, So
Na = Nb
Also, B atoms are twice as heavy as A atoms
Wb = 2*Wa
Total weight of alloy = 600 Pound
Wa + Wb = 600 pounds
Since Wb = 2*Wa, So
Wa + 2*Wa = 600
3*Wa = 600
Wa = Weight of A atoms = 200 pounds
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A certain alloy is a mixture of equal number A atoms and B atoms. B atoms...
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