An employee sample estimated the standard deviation of emails received per day to be 155 emails. You are researching the average emails received per day. You want to know how many employees you should survey if you want to know, at a 90% confidence level, that the sample mean emails per day is within 47 emails of the true mean emails per day.
Use Excel to find the value for z you should use to calculate a 90% confidence level.
Round your answer to three decimal places.
An employee sample estimated the standard deviation of emails received per day to be 155 emails....
A professor's sample estimated the standard deviation of missing assignments to be 3. You are researching the average missing assignments. You want to know how many people you should survey if you want to know, at a 90% confidence level, that the sample mean amount of missing assignments is within 1 assignments of the true mean number of missing assignments. Use a calculator to find the z- value that you should you use to calculate the 90% confidence level. Round...
The days of training a new employee needs are normally distributed with a population standard deviation of 3 days and an unknown population mean. If a random sample of 23 new employees is taken and results in a sample mean of 18 days, use Excel to find a 90% confidence interval for the population mean. Round the final answer to two decimal places.
A population is estimated to have a standard deviation of 12. We want to estimate the population mean within 2 with a 99 percent level of confidence. How large a sample is required?
a) Battery life for a hand-held computer is normally distrbuted and has a population standard deviation of 3 hours. Suppose you need to estimate a confidence interval estimate at the 95% level of confidence for the mean life of these batteries. Determine the sample size required to have a margin of error of 0.253 hours. Round up to the nearest whole number. b)The managers of a company are worried about the morale of their employees. In order to determine if...
In a simple random sample of 64 households, the sample mean number of personal computers was 1.17. Assume the population standard deviation is σ = 0.23. 19) Why can we say the sampling distribution of the sample mean number of personal computers is approximately normal? 20) Construct a 98% confidence interval for the mean number of personal computers. Interpret this interval. 21) The population standard deviation for the height of high school basketball players is three inches. If we want...
A population is estimated to have a standard deviation of 12. We want to estimate the population mean within 2, with a 95% level of confidence. How large a sample is required? (Round up your answer to the next whole number.)
A population is estimated to have a standard deviation of 10. We want to estimate the population mean within 2, with a 95% level of confidence. How large a sample is required? a. 98 b. 97 c. 96 d. 95
The population standard deviation for the typing speeds for secretaries is 4 words per minute. If we want to be 90% confident that the sample mean is within 1 word per minute of the true population mean, what is the minimum sample size that should be taken? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table above for the z-score, and be sure to round up to the nearest integer.
You wish to estimate the mean number of travel days per year for salespeople. The mean of a small pilot study was 150 days, with a standard deviation of 36 days. If you want to estimate the population mean within 7 days, how many salespeople should you sample? Use the 90% confidence level.
A professional employee in a large corporation receives an average of µ = 41.7 e-mails per day. An anti-spam protection program was installed in the company's server and one month later a random sample of 45 employees showed that they were receiving an average of ?̅= 36.2 e-mails per day. Assume that ơ = 18.45. Use a 5% level of significance to test whether there has been a change (either way) in the average number of emails received per day...