Question

A human gene carries a certain disease from a mother to her child with a probability rate of 0.54. That is, there is a 54% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has five children. Assume that the infections, or lack thereof, are independent of one another. Find the probability that all five of the children get the disease from their mother. Question 16 options: 0.024 0.954 0.046 0.021

Answer 1

Given : n=5 , p=0.54 , q=1-p=0.46

Here ,

The pmf of X is ,

; x=0,1,2,..........,n

=0 ; otherwise

Therefore ,

Hence , the probability that all five of the children get the disease from their mother is 0.046.