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1. I placed 5 mL of 0.025 M CuSO4 in a test tube, and slowly added...

1. I placed 5 mL of 0.025 M CuSO4 in a test tube, and slowly added 15 M NH3 until my solution turned blue, I then removed reactant by adding (CuSO4, NH3, H20, HCl, NaOH) and my test tube appeared clear, light light blue. That's because as I removed reactant, the Cu2+ concentration (increased, decreased, stayed the same)

2. In a medium test tube, I added 2 drops of 6 M NaOH to 5 mL of 0.05 M MgCl2(aq) to form the precipitate, Mg(OH)2(s), establishing the equilibrium system: Mg(OH)2(s) <--> Mg2+(aq) + 2 OH–(aq). I then used a reagent in lab to stress the system. The reagent I used, was most likely a few drops of 6 M HCl. If I decrease the OH- concentration, the concentration of Mg2+ will (increase, decrease, stay the same). But if instead I increase the OH- concentration the concentration of Mg2+ will (increase, decrease, stay the same).

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