Prove or disprove that 7n=O(5n) + 7.
7n = O(5n) + 7
=> 7n - 7 = O(5n)
if f(n) = O(g(n)) then f(n) <= cg(n) for all n>=n0
Assume 7n - 7 = O(5n) is True
Then we need to find a c>0 and n0 for which (7n-7) <=
c(5n)
Let c = 7/5 (>0)
Then (7/5)*5n = 7n
and 7n > (7n-7) for all n>=0
Here Our Assumption is True.
Therefore 7n=O(5n) + 7 is True
Prove or disprove the following statements, using the relationship among typical growth-rate functions seen in class. a)n^15log n + n^9 is O(n^9 log n) b) 15^7n^5 + 5n^4 + 8000000n^2 + n is Θ(n^3) c) n^n is Ω (n!) d) 0.01n^9 + 800000n^7 is O(n^9) e) n^14 + 0.0000001n^5 is Ω(n^13) f) n! is O(3n)
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7n +(-1)" For the given sequence {anina, where an =- find 5n the least upper bound - LUB, the greatest lower bound - GLB and its limit, if they exist. a) There is no LUB, GLB = 0; Diverges 3 b) LUB 6 5 GLB = ; Converges to 7 5 9 2 6 7 c) LUB 3 2 GLB = Converges to 9 5 5 d) LUB 3 GLB = 2' 6 5 Diverges 7 6 e) LUB GLB...
#7
7 Prove or disprove: If H is a normal subgroup of G such that H and G/H are abelian, then G is abelian. If G is cyclic, prove that G/H must also be cyclic. 8.
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Prove or Disprove #3
(d) For each of the following, prove or disprove: iii) There is an element of X × Y with the form (a, 3a)
(d) For each of the following, prove or disprove: iii) There is an element of X × Y with the form (a, 3a)
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