Calculate the pH of a solution that is 0.50 M in HF (Ka = 7.2 x10-4) and1.50 M in NaF. A. 10.56 B. 3.62 C. 3.44 D. 0.30 E. 3.14
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Calculate the pH of a solution that is 0.50 M in HF (Ka = 7.2 x10-4)...
1.) You have two buffered solutions. Buffered solution 1 consists of 5.0 M HOAc and 5.0 M NaOAc; buffered solution 2 is made of 0.050 M HOAc and 0.050 M NaOAc. How do the pHs of the buffered solutions compare? (Note: Ac– = acetate ion, CH3COO–). A. The pH of buffered solution 1 is greater than that of buffered solution 2. B. None of the answers are correct C. The pH of buffered solution 1 is equal to that of...
Calculate the pH of a solution that is 1.50 M in HCN (Ka = 6.2 x10-10) and 0.50 M in NaCN. A. 3.44 B. 8.73 C. 9.68 D. 9.21 E. 3.63
1. Calculate the pH of a solution that is 1.00 M HF, 1.00 M HCl, and 1.439 MNaF. (Ka= 7.2 x10–4) 3.14 3.30 2.48 2.98 0.25 I am getting 2.48 for this one 2. Calculate the pH of a solution that is 1.00 MHF, 2.00 M HCl, and 1.439 MNaF. (Ka= 7.2 x10–4) 3.14 3.30 2.48 2.98 0.25 and for the second one i keep getting 2.48 or 0.25. Which one is it??
6. Calculate the pH of a solution that is 0.60 Min HF (Ka = 7.2 x 10 ) and 0.80 Min NaF.
A 1.0-liter solution contains 0.25 M HF and 0.32 M NaF (Ka for HF is 7.2 × 10–4). What is the pH of this solution
Find the pH and percent ionization for each HF solution. (Ka for HF is 6.8 x10-4.) Please use this Ka that is given to solve a. 0.250 M HF b. 0.100 M HF c. 0.050 M HF
Calculate the pH and [H3O+] of a buffer solution consisting of 0.50 M HF (Ka = 6.8 × 10-4) and 0.45 M KF.
calculate the pOH and pH of a 0.025 M HF. Ka= 3.0 x10^(-4).
Determine the pH of a solution that is 1.00 L of 0.100 M HF and 0.100 M NaF after 0.50 mole of solid KOH has been added to the solution. Ka(HF) = 3.5×10-4
HELP! Exam tomorrow!! Calculate the pH of a solution that is 2.00 M HF, 1.00 M NaOH, and 0.500M NaF n 1.00 L of the solution. Ka for HF = 7.2 x 10-4) HF(aq) + OH-(aq)-->F-(aq) + H2O(l) Correct answer is 3.32 really need help with the set up!! How many moles of solid NaF would have to be added to 1.0 L of 1.90 M HF solution to achieve a buffer of pH 3.35? Assume there is no volume...