Can you answer the following showing workings out and formula used.
The length of a screw manufactured by a company is normally distributed with mean 2.5cm and a standard deviation 0.1cm. Specifications call for the lengths to range from 2.4cm to 2.6 cm.
a, What proportion of parts will be greater than 2.65cm?
b, What length is exceeded by 10% of the parts?
c, What percentage of parts will not meet the specification?
d, If you randomly pick three of those items, what would be the probability that exactly two of them will meet the specification?
Can you answer the following showing workings out and formula used. The length of a screw...
Can you answer the following showing formula used and all workings out. The length of a screw manufactured by a company is normally distributed with mean 2.5cm and a standard deviation 0.1cm. Specifications call for the lengths to range from 2.4cm to 2.6cm. 1, what value of standard deviation is required so that less than 7% of screws have a length greater than 2.8cm? 2, another manufacturer produces the same screw for which 15% of the screws have length less...
Can someone please help me with my central limit theorem homework? Thank you much! 1. A population has parameters μ=36.3 and 57.1. You intend to draw a random sample of size n=139. a. What is the mean of the distribution of sample means? μ¯x= _________________ b. What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.) σx¯=_______________ 2. A population of values has a normal distribution with μ=201.8μ=201.8 and σ=90.9σ=90.9. You intend...
I just need the answer for E and F, thank you:) Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean p=123 days and standard deviation = 13 days. Complete parts (a) through (1) below. (a) What is the probability that a randomly selected pregnancy lasts less than 118 days? The probability that a randomly selected pregnancy lasts less than 118 days is approximately 0.3503). (Round to four decimal places as needed.) Interpret this...