The pH of a 0.30 M solution of a weak base is 10.82.
What is the Kb of the base?
pOH =14- pH= 14-10.82=3.81
pOH = - log[OH-]
= -log 10-3.81
= - log 1.55 ×10-4
[OH-] = 1.55× 10^-4
[OH-] =√KbC,
C= .3 M
Kb=[OH-]^2/C=( 1.55×10^-4)^2/.3
= 8 × 10^-8
Enter your answer in the provided box. Determine the Kb of a weak base if a 0.30 M solution of the base has a pH of 11.98 at 25 ° C.
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