A 0.14-kg ball is placed in a shallow wedge with an opening angle of 160 ∘...
A 0.14-kg ball is placed in a shallow wedge with an opening angle of 160 ∘ , as shown in the figure (Figure 1). You may want to review (Pages 170 - 172) .
part A: For each contact point between the wedge and the ball, determine the force exerted on the ball. Assume the system is frictionless. Determine the Contact force 1.
part b: Determine the Contact force 2.
Homework Answers
Vertical component of force,
Fy = mg/2 = (0.14 x 9.8)/2 = 0.686 N
Angle, theta = (180 - 160)/2 = 10°
Force, F = 0.686/cos(10) = 0.697 N
Contact force 1 = 0.697 N
Contact force 2 = 0.697 N
Comment in case any doubt please rate my answer....
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