A solution is prepared by dissolving 0.23 moles of chloroacetic acid and 0.27 moles of sodium chloroacetate in water sufficient to yield 1.00L of solution. The addition of 0.05 mole of HCl to this buffer solution causes the pH to drop slightly. The pH does not decrease drastically because the HCl reacts with the.........present in the buffer solution. The Ka of chloroacetic acid is 1.36*10^-3.
The answer is:
the PH does not decrease drastically because the HCl reacts with the CHLOROACETATE ion present in the buffer solution.
HCl dissociates as H+ + Cl-
chloroacetate is ClCH2COO-
the reaction is : ClCH2COO- + H+ = ClCH2COOH
as the H+ is getting reacted so PH is droping slightly.
A solution is prepared by dissolving 0.23 moles of chloroacetic acid and 0.27 moles of sodium...
A solution is prepared by dissolving 0.23 mol of formic acid and 0.27 mol of sodium formate in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the present in the buffer solution. The K, of formic acid is 1.8 x 10+ A formic acid B. sodium formate C water D. sodium E....
1. A solution is prepared by dissolving 0.23 mol of butanoic acid and 0.27 mol of sodium butanoate in water sufficient to yield 1.00 L of solution. The addition of 0.0O5 mol of HCI to this buffer solution causes the plH to drop slightly. The pH does not decrease drastically because the HCl reacts with the present in the buffer solution. The Ka of butanoic acid is 1.36x 10-3 A) H20 в) Нзо+ butanoate ion D butanoic acid AlE) This...
16) The molar concentration of hydronium ion in pure water at 25°C is 1.0 x 10 b) 0.00 c) 1.0 x 1014 d) 1.0 e) 7.00 17) A solution is prepared by dissolving 0.23 mol of hydrazoic acid and 0.27 mol of sodium azide in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts...
15) The pH of a 0.63 M aqueous solution of hypobromous acid, HBrO, at 25°C is 4.17. What is the value of K for HBro? a) 2.0 x 10 b) 1.1 x 10 c) 1.08 x 10° d) 7.34 x 10 e) 6.8 x 10 16) The molar concentration of hydronium ion in pure water at 25°C is (á) 1.0 x 10? b) 0.00 c) 1.0 x 1024 d) 1.0 e) 7.00 117) A solution is prepared by dissolving 0.23...
questions 9,10 and 11 please! thank you lying 0.23 mol of hypochlorous acid and 0.27 mol of sodium fent to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this to increase slightly. The pH does not increase drastically because the present in the buffer solution. The Ka of hypochlorous acid is A solution is prepared by dissolu hupachlorite in water sufficien buffer solution causes the pH toinen NaOH reacts with the 30.10-8 Ohypochlorous acid B)...
Calculate the pH of a solution prepared by dissolving 0.876 moles of carbonic acid (H2CO3) and 0.543 moles of sodium hydrogen carbonate (NaHCO3) in water sufficient to yield 1.00 L of solution. The Ka of carbonic acid is 4.5x10^-7. Explain answer please
a buffer solution of pH =5.30 can be prepared by dissolving acetic acid and sodium acetate in water. How many moles of sodium acetate must be added to 1 L of 0.25 M acetic acid to prepare the buffer? Ka(CH3COOH)=1.8 x 10^-5
A solution is prepared at 25° that is initially 0.39M in chloroacetic acid HCH2ClCO2, a weak acid with =Ka×1.310−3, and 0.064M in potassium chloroacetate KCH2ClCO2. Calculate the pH of the solution. Round your answer to 2 decimal places
A solution was prepared by dissolving 0.200 moles of sodium hypoch lorite (NaClO) in water to a final volume of 1.00 Liter. Ka 2.96x10 for hypochlorous acid (HCIO). Show equations and work steps for these calculations. 1) Calculate Kb of sodium hypochlorite. 2) Calculate the pH of the NaClO solution. 3) Calculate the pH if 10.0 mL of 1.00 M HCl is added to 100.0 mL of the original NACIO solution. 4) Calculate the pH if 20.0 mL of 1.00...
A buffer solution is prepared by dissolving 1.000 g of sodium acetate (CH3COONa) into 100.00 mL of a 0.100 M solution of acetic acid. Then 2.00 mL of a 1.00 M solution of hydrochloric acid is added to the acetic acid/sodium acetate buffer solution. The Ka of acetic acid is 1.8 × 10−5. What is the pH of HCl?