Construct the confidence interval for the population mean. Assume that the population has a normal distribution....
construct a 95% confidence interval for the population mean, Assume the population has a normal distribution. A sample of 20 part-time workers had a mean annual earnings of $3120 with a standard deviation of $677. Round to the nearest dollar. *Please STEP out the problem clearly for me.
A) Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c = 0.99, x equals = 12.4, s = 4.0, n =7 ( ? , ? ) (Round to one decimal place as needed.) B) The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed. 1424 1224 980 697 730 834 723...
Construct the indicated confidence interval for the population
mean μ using the t-distribution. Assume the population is normally
distributed.
Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed c-0.98, x-12.4, s 0.91, n 13 Round to one decimal place as needed.)
Construct the indicated confidence interval for the population mean using the t-distribution. Assume the population is normally distributed. c=0.99, x =14.3, s=2.0 n=5
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Construct the indicated confidence interval for the population mean y using the t-distribution. Assume the population is normally distributed c=0.90, x= 14.6, s = 2.0, n= 10 The 90% confidence interval using a t-distribution is (Round to one decimal place as needed.)
Construct the indicated confidence interval for the population mean mu using the t-distribution. Assume the population is normally distributed. C= 0.99 , X= 14.7 S = 4.0 , N= 9 ; C= 0.98 , X= 12.6 S = .89 , N= 19
Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c =0.99, x overbar =14.6, s=4.0, n=8
Construct the indicated confidence interval for the population mean muμ using the t-distribution. Assume the population is normally distributed. cequals=0.990.99, x overbarxequals=12.412.4, sequals=2.02.0, nequals=88 The 99% confidence interval using a t-distribution is left parenthesis nothing comma nothing right parenthesis .,. (Round to one decimal place as needed.)