Use standard enthalpies of formation to determine the ΔHo in kJ for the following reaction: 4NH3(g)...

Question

Question

Use standard enthalpies of formation to determine the ΔHo in kJ for the following reaction:

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)

ΔHfo (NH3(g)) = -45.90 kJ/mol

ΔHfo (NO(g)) = 90.29 kJ/mol

ΔHfo (H2O(g)) = -241.83 kJ/mol

Answer 1

Answer #1

∆H=4∆H_f(NO) +6∆H_f(H2O) -5∆H_f(O2) -4∆H_f(NH3)

∆H=(4*90.29) +(6*-241.83) -5(0) -(4*-45.90)

∆H=361.16-1450.98+183.6

∆H=−906.22 KJ

Answer 2

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