Question

The customer service center in a department store has determined that the amount of time spent...

The customer service center in a department store has determined that the amount of time spent with a customer about a complaint is normally distributed with a mean of 9.3 minutes and a standard deviation of 2.5 minutes.

a. What is the z-value that corresponds to x =10 minutes.

b. What is the z-value that corresponds to x =5 minutes

c. what is the x-value that corresponds to z = 1.12? Round answer to the nearest whole number.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

For the given normal distribution with a mean of 9.3 minutes and a standard deviation of 2.5 minutes.

a) Z score is calculated as:

b) Z is calculated as:

c) At Z score 1.12 the X value is calculated as:

X=12 rounded to whole no.

Add a comment
Know the answer?
Add Answer to:
The customer service center in a department store has determined that the amount of time spent...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The Customer Service Center in a large New York department store has determined that the amount...

    The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.7 minutes and a standard deviation of 2.0 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...

  • The Customer Service Center in a large New York department store has determined that the amount...

    The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.1 minutes and a standard deviation of 2.8 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...

  • The Customer Service Center in a large New York department store has determined that the amount...

    The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 8.7 minutes and a standard deviation of 3.0 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes (b) longer...

  • The Customer Service Center in a large New York department store has determined that the amount...

    The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.1 minutes and a standard deviation of 2.7 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places.) (a) less than 10 minutes Incorrect: Your...

  • 2. 8 points BBBasicStat6 7.R.016. My Notes The Customer Service Center in a large New York...

    2. 8 points BBBasicStat6 7.R.016. My Notes The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.3 minutes and a standard deviation of 2.5 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount of time spent resolving the complaint will be as follows. (Round your answers to four decimal places)...

  • Find z such that 7% of the area under the standard normal curve lies to the...

    Find z such that 7% of the area under the standard normal curve lies to the right of z. (Round your answer to two decimal places.) My Notes Ask Your Find z such that 56% of the standard normal curve lies between-z and z. (Round your answer to two decimal places.) My Notes Ask Your The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint...

  • 1. Find z such that 70% of the standard normal curve lies between −z and z....

    1. Find z such that 70% of the standard normal curve lies between −z and z. (Round your answer to two decimal places.) 2. The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.3 minutes and a standard deviation of 2.3 minutes. What is the probability that for a randomly chosen customer with a complaint, the amount...

  • At a customer service call center for a large company, the number of calls received per...

    At a customer service call center for a large company, the number of calls received per hour is normally distributed with a mean of 120 calls and a standard deviation of 5 calls. What is the probability that during a given hour of the day there will be less than 132 calls, to the nearest thousandth?

  • a) Sketch the area under the standard normal curve over the indicated interval and find the...

    a) Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the right of z = 1.51 is ____ b) The Customer Service Center in a large New York department store has determined that the amount of time spent with a customer about a complaint is normally distributed, with a mean of 9.5 minutes and a standard deviation of 2.1 minutes. What is...

  • The time required for an automotive center to complete and change service on an automobile primately...

    The time required for an automotive center to complete and change service on an automobile primately follows anomalion, with a man of 15 minutes and a standard deviation (a) The automotive center quanto customers that the service will take no longer than 20 minutes ir does take longer the customer will receive the service for all price. What percent of customers the si half price (1) of the automotive Center does not want to give the discount to more than...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT