In a test of Upper H 0H0: muμequals=100 against Upper H Subscript aHa: muμnot equals≠100, the...
In a test of
Upper H 0H0:
muμequals=100
against
Upper H Subscript aHa:
muμnot equals≠100,
the sample data yielded the test statistic
z equals 2.16z=2.16.
Find the
Upper PP-value
for the test.
Homework Answers
this is the two tailed test .
The null and alternative hypothesis is ,
H0 : 
= 100
Ha :
100
Test statistic = z=2.16
P(z >2.16 ) = 1 - P(z < 2.16 ) = 1 -0.9846=0.0154
P-value = 2*0.0154=0.0308
Add Answer to:
In a test of
Upper H 0H0:
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Upper H Subscript aHa:
muμnot equals≠100,
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