An injection molding system has a first cost of $150,000 and an annual operating cost of $77,000 in years 1 and 2, increasing by $4,500 per year thereafter. The salvage value of the system is 25% of the first cost regardless of when the system is retired within its maximum useful life of 5 years. Using a MARR of 14% per year, determine the ESL and the respective AW value of the system.
The ESL is _____ year(s) and AW value of the system is $_____.
The ESL is 5 year(s) and AW value of the system is -$119,498.63
We find this using the table below. Salvage value is fixed at 25% of 150000 = 37500. Annual cost is increasing by 4500 from 3rd year. We find the cumulative PV of all annual costs and all salvage values for all 5 years separately using PV = cash flow in year n * (1 + 15%)^-n.
Then we find the net present value by adding initial cost of 150000 to these two figures for all years. Finally using (A/P, 15%, n) for the net present value to get EUAC. Note that AW = -EUAC.
Year | Annual cost | Salvage value | PV of the annual cost | PV of the market value | Net present value | EUAC |
1 | 77000 | 37500 | 67543.86 | 32894.74 | 184649.12 | 210500.00 |
2 | 77000 | 37500 | 126792.86 | 28855.03 | 247937.83 | 150570.09 |
3 | 81500 | 37500 | 181803.04 | 25311.43 | 306491.61 | 132015.58 |
4 | 86000 | 37500 | 232721.94 | 22203.01 | 360518.93 | 123731.82 |
5 | 90500 | 37500 | 279724.81 | 19476.32 | 410248.48 | 119498.63 |
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