Question

A golfer hits a ball from the origin with an initial speed of 30m/s at an angle of 50 degrees above the horizon. The ball lands on a green that is 5m above the level where the ball was struck

Find(a) How long the ball is in the air?

Find (b) How far has the ball traveled in the horizontal direction when it lands?

Answer 1

a)

using 2nd equation of motion

h = v sin x * t - 0.5 gt^2

5 = 30 sin 50 * t - 4.9 t^2

solving for t

t = 4.461 s

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b)

D = v cos x* t

D = 30 cos 50 * 4.461

D = 86.02 m

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note: there are two time when it reach 5 m above the striking point, i've considered the far point.

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