30.0 mL of 0.340M C5H5N (Pyridine Kb = 1.7 x 10-9) is titrated with 0.190M HBr...
30.0 mL of 0.340M C5H5N (Pyridine Kb = 1.7 x 10-9) is titrated with 0.190M HBr (hydrobromic acid). Determine the pH at each of the following points.
a. Before any HBr is added
b. After 3.00mL of HBr is added
c. at half titration
d. at equivalence
e. After 0.50 mL of HBr added after the equivalence point
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30.0 mL of 0.340M C5H5N (Pyridine Kb = 1.7
x 10-9) is titrated with 0.190M HBr...
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