A toroid has an inside diameter of 40.0 cm and an outside diameter of 45.0 cm. It conducts a current of 30.0 A in its 700 turns. The magnetic field at a distance of 42 cm from its center is:
a. 50 mT
b.30 mT
c.20 mT
d.10 mT
Solution)
Given,
Inside Diameter, D=40 cm
Radius, r=20*10^-3 m
Outside diameter=45 cm
Current, I=30 A
No of turns, N=700
Distance, r=0.42 m
We know,
Magnetic Field, B=uoNI/2pi*r
On substituting values,
B=((2*10^-7)*700*30)/0.42=0.1 mT (option d)------Ans
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A toroid has an inside diameter of 40.0 cm and an outside diameter of 45.0 cm....
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