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an experiment consits of tossting 6 not weighted coins except 1 of the 6 has a...

an experiment consits of tossting 6 not weighted coins except 1 of the 6 has a head on both sides. compute the probability of obtaining 4 heads
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Answer #1

Out of the 6 coins, 1 has heads on both sides so it will always show heads. Other 5 are fair so Probability of getting heads there is 1/2

Now when we toss the 6 coins, probability of getting heads on exactly 4= Probability of getting 0 heads on the 1 fair ones*1 (since the 1 coin will always show heads)

= 1C0*(1/2)^1 = 0.5

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