A sample of Ar gas with a volume of 48.6 mL at 610 torr is compressed...
A sample of Ar gas with a volume of 48.6 mL at 610 torr is compressed at constant temperature until its volume is 32.7 mL. What will be the new pressure of the sample in torr?
Homework Answers
We use charles law
V1/T1=V2/T2
V1= 48.6ml
T1= 610 torr
V2= 32.7 ml
T2= 32.7*610 /48.6 =410.4 torr the new pressure
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