The diameter of a brand of tennis balls is approximately normally distributed, with a mean of 2.71 inches and a standard deviation of 0.05 inches. A random sample of 11 tennis balls is selected. What is the probability that the sample mean is between 2.70 and 2.72 inches
SOLUTION:
From given data,
The diameter of a brand of tennis balls is approximately normally distributed, with a mean of 2.71 inches and a standard deviation of 0.05 inches. A random sample of 11 tennis balls is selected. What is the probability that the sample mean is between 2.70 and 2.72 inches.
Mean = = 2.71
Standard deviation = = 0.05
Sample size = n = 11
Then,
= = 2.71
= / sqrt(n) = 0.05 / sqrt(11) = 0.01507
Z = ( - ) / = ( - 2.71) / 0.01507
Now,
The probability that the sample mean is between 2.70 and 2.72 inches.
P (2.70 < < 2.72) = P ((2.70 - 2.71) / 0.01507 < ( - ) / < (2.72 - 2.71) / 0.01507)
P (2.70 < < 2.72) = P (-0.01/ 0.01507 < Z < 0.01 / 0.01507)
P (2.70 < < 2.72) = P (-0.66 < Z < 0.66)
P (2.70 < < 2.72) = P (Z < 0.66) - P (Z < - 0.66 )
P (2.70 < < 2.72) = 0.74537 - 0.25463
P (2.70 < < 2.72) = 0.49074
The probability that the sample mean is between 2.70 and 2.72 inches is 0.49074.
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