A child sitting 1.90 m from the center of a merry-go-round moves with a speed of...
A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.15 m/s .
Part A: Calculate the centripetal acceleration of the child.
Part B: Calculate the net horizontal force exerted on the child. (mass = 28.5 kg )
Homework Answers
The centripetal acceleration is towards the center and is given by a =v^2/r
=(2.15)^2 / 1.90
= 2.433 m/s^2
(b) Net force in horizontal is centripetal force acting towards the center
F = ma
=28.5× 2.433
=69.2405 N
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