Question

A sales manager for an advertising agency believes there is a relationship between the number of...

A sales manager for an advertising agency believes there is a relationship between the number of contacts and the amount of the sales. To verify this, the following data was collected:
Sales ($)   Contacts
25,000   15
16,000   15
28,000   20
60,000   18
80,000   46
35,000   24
85,000   45
80,000   45
95,000   55
110,000   52
Which is the:
Independent variable?   ___________________

Dependent variable?   ___________________

Calculate the coefficient of correlation and interpret the results.

Determine both the coefficient of determination and non-determination and explain the result.


Determine the unrounded regression equation for this data set.

Using the regression equation predict the amount of sales when 50 contacts are made. Show all work involved in finding your answer.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here independent variable is Number of contacts

Dependent variable is Sales (In thousands)

Here coefficient of correlation is calculated with the help of values of , , , ,

Contacts(x) Sales ($)(y) x^2 xy y^2
15 25 225 375 625
15 16 225 240 256
20 28 400 560 784
18 60 324 1080 3600
46 80 2116 3680 6400
24 35 576 840 1225
45 85 2025 3825 7225
45 80 2025 3600 6400
55 95 3025 5225 9025
52 110 2704 5720 12100
Sum 335 614 13645 25145 47640

Correaltion coefficient r = [n(Σxy) - (Σx)((Σy)] / sqrt [ (n (Σx2 ) - (Σx)2) ( n (Σy2 ) - (Σy)2)]

r = [10 * 25145 - 335 * 614]/ [(10 * 13645 - 335 * 335) * (10 * 47640 - 335 * 335)]

r = 0.9325

Here as the correlation coefficient is near to 1 that means there is strong positive correlation between number of contacts and sales.

Here let say the regression equation is

y^ = a + bx

a = [(Σy) (Σx2 ) - (Σx) (Σxy)]/ [ n (Σx2 ) - (Σx)2 ]

a = [614 * 13645 - 335 * 25145]/ [10 * 13645- 335 * 335]

a = -1.88

b = [ n(Σxy) - (Σx)((Σy)]/ [ n (Σx2 ) - (Σx)2 ]

b = [10 * 25145 - 335 * 614]/ [10 * 13645- 335 * 335]

b = 1.889

y^ = -1.88 + 1.889x

where x = number of contacts

y^ = predicted value of sales (in thousands dollars)

Here if x = 50

y^ = -1.88 + 1.889 * 50

y^ = $92568 is  the amount of sales when 50 contacts are made.

Add a comment
Know the answer?
Add Answer to:
A sales manager for an advertising agency believes there is a relationship between the number of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • QUESTIONS sales manager for an advertising agency believes that there is a relationship between the number...

    QUESTIONS sales manager for an advertising agency believes that there is a relationship between the number of contacts that a salesperson makes and the amount of salos dollars eamed. What is the independent variable? A Salesperson B. Number of contacts Amount of sales D. Sales manager QUESTION 9 A regression analysis yields the following information: Y = 2.21+1.49X; n = 10:8-1.66: EX - 32:2(x-x) = 31.6 Compute the 95% prediction interval when X = 4. A (0.0, 4.05 ) B.(2.67.5.33)...

  • 1 Problem 7 (20 marks) A sales manager for an advertising agency believes there is a...

    1 Problem 7 (20 marks) A sales manager for an advertising agency believes there is a relationship between the number of contacts and the amount of the sales. To verify this believe, the following data was collected: Salesperson Number of Contacts Sales (in thousands) 14 24 2 12 14 3 20 28 4 16 30 16 80 23 7 48 90 50 85 55 120 10 SO 110 6 8 9 Assume normality of variables. a) Calculate the coefficient of...

  • 1 Problem 8 (20 marks) A sales manager for an advertising agency believes there is a...

    1 Problem 8 (20 marks) A sales manager for an advertising agency believes there is a relationship between the number of contacts and the amount of the sales. To verify this belief, the following data was collected: Salesperson Number of Contacts Sales (in thousands) 14 24 2 12 14 3 20 28 4 16 30 5 46 80 6 23 30 7 48 90 8 50 85 55 120 10 50 110 9 Assume normality of variables. a) Calculate the...

  • QUESTION 23 A sales manager for an advertising agency believes that there is a relationship between...

    QUESTION 23 A sales manager for an advertising agency believes that there is a relationship between the number of contacts that a sales person makes and the amount of the sales dollars earned. A regression analysis shows the following results: Coefficients Standard Error T Stat P-value Intercept -12 201 6.560 -1.860 0.100 Number of Contacts 2.195 0.176 12.505 0.000 What is the standard error of the slope? -0.176 6.560 -12.201 12.50

  • QUESTION 12 A sales manager for an advertising agency believes that there is a relationship between...

    QUESTION 12 A sales manager for an advertising agency believes that there is a relationship between the number of contacts that a sales person makes and the amount of the sales dollars earned. A regression ANOVA shows the following results: ANOVA F P.value df 1.00 8.00 Regression Residual Total 156.38 SS 13555.42 693.48 14248.90 MS 13555.42 86.68 0.00 9.00 What is the value of the standard error of estimate? 8.328 8.778 86.68 9.310

  • QUESTION 5 A sales manager for an advertising agency believes that there is a relationship between...

    QUESTION 5 A sales manager for an advertising agency believes that there is a relationship between the number of contacts that a sales person makes and the amount of the sales dollars carned. A regression analysis shows the following results: Coefficients Standard Error T Stat P-value Intercept -12.201 6.560 -1.860 0.100 Number of Contacts 2.195 0.176 12.505 0.000 What is the decision regarding the hypothesis that the slope equals zero? Reject Ha. Fail to reject Ho. Fail to reject Ha....

  • Mr. James, president of Daniel-James Financial Services, believes that there is a relationship between the number...

    Mr. James, president of Daniel-James Financial Services, believes that there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, he gathered the following information from a sample of clients for the last month. Let X represent the number of times that the client was contacted and Y represent the value of sales ($1000) for each client sampled. Number of` Sales Contacts (X) ($1000) (Y) 14    24 12 14 20...

  • QUESTION 4 (3 points) A sales manager for an adve of contacts and the amount of the sales. To verify this believe, the following data was collected rtising agency believes there is a relationship...

    QUESTION 4 (3 points) A sales manager for an adve of contacts and the amount of the sales. To verify this believe, the following data was collected rtising agency believes there is a relationship between the number Number of Salesperson Contacts. Sales lin thousands 12 20 28 4 80 23 85 120 110 10 What is the 95% confidence interval for sales (in thousands) for someone who made 30 contacts? A. 51.5 to 55.8 B. 51.4 to 55.9 C. 46.7...

  • Q3. (15 points) The managing partner of an advertising agency believes that his company's sales are...

    Q3. (15 points) The managing partner of an advertising agency believes that his company's sales are related to the industry sales ($ 1000s). He uses Microsoft Excel to analyze the last 4 years of quarterly data (i.e., n=16) with the following results: Regression Statistics Multiple R 0 .802 R Square - 0.643 Adjusted R Square 0.618 Standard Error SYX Observations 0.9224 ANOVA df 1 14 15 F 25.27 Regression Error Total MS 21.497 0.851 Sig.F 0.000 SS 21.497 11.912 33.409...

  • Mr. James McWhinney, president of Daniel James Financial Services, believes there is a relationship between the...

    Mr. James McWhinney, president of Daniel James Financial Services, believes there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, Mr. McWhinney gathered the following sample information. The X column indicates the number of client contacts last month and the Y column shows the value of sales ($ thousands) last month for each client sampled. Number of Contacts, x 14 12 20 16 46 Sales ($ thousands) 24 14 28...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT