An air-standard Brayton cycle includes a regenerator which is shown in the below figure. The air...
An air-standard Brayton cycle includes a regenerator which is shown in the below figure. The air enters the compressor at 100 kPa, 20℃. The pressure ratio across the compressor is 9:1. The highest temperature in the cycle is 1100℃, and the flow rate of the air is 10 kg/s. The regenerator operates at effectiveness 80 percent. Both the efficiencies of the turbine and the compressor are 85%. Do not use Table A-22. Assuming constant specific heat ( cp = 1.004 kJ/kg/K; cv = 0.717 kJ/kg/K; k = 1.40), calculate:
1) the compressor power,
2) the turbine power,
3) the rate of heat added to the cycle,
4) the thermal efficiency of the cycle,
5) now find the thermal efficiency of cycle without the regenerator and find the percent change in thermal efficiency when the regenerator is added.
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An air-standard Brayton cycle includes a regenerator which is
shown in the below figure. The air...
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at 100 kPa, 300...
Air enters the compressor of a cold air-standard Brayton cycle with regeneration at 100 kPa, 300 K, with a volume flow rate of 5 m3/s. The compressor pressure ratio is 8, and the turbine inlet temperature is 1400 K. The turbine and compressor each have isentropic efficiencies of 80% and the regenerator effectiveness is 80%. For the air, k = 1.4 and the ambient temperature is T0 = 300 K. -Determine the thermal efficiency of the cycle. -determine the back...
Air enters the compressor of a regenerative air-standard Brayton cycle with a volumetric flow rate of...
Air enters the compressor of a regenerative air-standard Brayton cycle with a volumetric flow rate of 100 m3/s at 0.8 bar, 280 K. The compressor pressure ratio is 20, and the maximum cycle temperature is 2100 K. For the compressor, the isentropic efficiency is 92% and for the turbine the isentropic efficiency is 95%. For a regenerator effectiveness of 86%, determine: (a) the net power developed, in MW. (b) the rate of heat addition in the combustor, in MW. (c)...
Air enters the compressor of a regenerative air-standard Brayton cycle with a volumetric flow rate of...
Air enters the compressor of a regenerative air-standard Brayton cycle with a volumetric flow rate of 20 m3/s at 0.8 bar, 280 K. The compressor pressure ratio is 20, and the maximum cycle temperature is 1950 K. For the compressor, the isentropic efficiency is 92% and for the turbine the isentropic efficiency is 95%. For a regenerator effectiveness of 86%, determine: (a) the net power developed, in MW. (b) the rate of heat addition in the combustor, in MW. (c)...
A Brayton cycle operates with regencration with air as the working fluid.
A Brayton cycle operates with regencration with air as the working fluid. Air enters the compressor at \(95 \mathrm{kPa}\) and \(290 \mathrm{~K}\) and the turbine at \(760 \mathrm{kPa}\) and \(1100 \mathrm{~K}\). Heat is transferred in the combustion region at a rate of \(75,000 \mathrm{~kJ} / \mathrm{s}\). The compressor Operates isentropically. The effectiveness of regenerator is \(80 \%\). The compressor and turbine operate is entropically. There are no pressure changes in the regenerator or combustion region. \(\mathrm{h}_{1}=290.16 \mathrm{~kJ} / \mathrm{kg}:\)\(\mathrm{h}_{2}=526.12 \mathrm{~kJ}...
Air enters the compressor of a cold air-standard Brayton cycle at 100 kpa, 300 k, with...
Air enters the compressor of a cold air-standard Brayton cycle at 100 kpa, 300 k, with a mass flow rate of 6 kg/s. the compressor pressure ratio is 10, and the turbine inlet temperature is 1400 K. For k = 1.4, calculate a. The thermal efficiency of the cycle b. The back work ratio c. The net power developed, in kW d. Reconsider the above with an ideal regenerator.
An ideal Brayton cycle with regeneration is shown below. Note that from 1 to 6, there...
An ideal Brayton cycle with regeneration is shown below. Note
that from 1 to 6, there is a heat rejection process. The pressure
ratio is 10 and the inlet to the compressor is at 300 K and 100
kPa. The maximum temperature is 1100 K. Use air as the working
fluid, and assume constant properties evaluated at 300
K.
(a) Find the net work output and the cycle efficiency assuming
the effectiveness of the regenerator is 100%
(b) Plot the...
Pressure ratio of a Brayton cycle with air operated regenerator 8. The lowest and highest temperatures...
Pressure ratio of a Brayton cycle with air operated regenerator 8. The lowest and highest temperatures of the cycle are 310 K and 1150 K. Adiabatic efficiency of compressor and turbine 75% and 82%, respectively. the efficiency of the regenerator is 65%. The cycle in the T-s diagram Show. Consider the variation of specific temperatures with temperature. a) the temperature of the air at the turbine outlet, b) Net work of the cycle, c) Calculate the thermal efficiency of the...
2. Air enters the compressor of a regenerative gas turbine engine at 310 K and 100...
2. Air enters the compressor of a regenerative gas turbine engine at 310 K and 100 kPa, where it is compressed to 900 kPa and 650 K. The regenerator has an effectiveness of 80%and the air enters the turbine at 1400 K. For a turbine isentropic efficiency of 90%, , then: (a) Sketch the T-s diagram of the cycle. (b) Determine the amount of heat transfer in the regenerator (c) Calculate the thermal efficiency of the cycle (d) Determine the...
Air enters the compressor of an air-standard Brayton cycle with a volumetric flow rate of 60...
Air enters the compressor of an air-standard Brayton cycle with a volumetric flow rate of 60 m3/s at 0.8 bar, 280 K. The compressor pressure ratio is 17.5, and the maximum cycle temperature is 2100 K. For the compressor, the isentropic efficiency is 92% and for the turbine the isentropic efficiency is 95%. Determine: (a) the net power developed, in kW. (b) the rate of heat addition in the combustor, in kW. (c) the percent thermal efficiency of the cycle.
Thermodynamics 2: STARTING FROM QS 2) 1) In an ideal Brayton cycle air enters the compressor...
Thermodynamics 2: STARTING FROM QS 2) 1) In an ideal Brayton cycle air enters the compressor at T = 300K and P = 1 bar with a volumetric flow rate = 20 m3/s. Air enters the turbine at P = 10 bar and T = 1800K. Find: a) The thermal efficiency b) The backwork ratio c) The net power generation in MW 2) For the same states above consider a cycle where the isentropic efficiency of the compressor and turbine...
Air enters the compressor of a regenerative air-standard Brayton cycle with a volumetric flow rate of 20 m3/s at 0.8 bar, 280 K. The compressor pressure ratio is 20, and the maximum cycle temperature is 1950 K. For the compressor, the isentropic efficiency is 92% and for the turbine the isentropic efficiency is 95%. For a regenerator effectiveness of 86%, determine: (a) the net power developed, in MW. (b) the rate of heat addition in the combustor, in MW. (c)...
A Brayton cycle operates with regencration with air as the working fluid. Air enters the compressor at \(95 \mathrm{kPa}\) and \(290 \mathrm{~K}\) and the turbine at \(760 \mathrm{kPa}\) and \(1100 \mathrm{~K}\). Heat is transferred in the combustion region at a rate of \(75,000 \mathrm{~kJ} / \mathrm{s}\). The compressor Operates isentropically. The effectiveness of regenerator is \(80 \%\). The compressor and turbine operate is entropically. There are no pressure changes in the regenerator or combustion region. \(\mathrm{h}_{1}=290.16 \mathrm{~kJ} / \mathrm{kg}:\)\(\mathrm{h}_{2}=526.12 \mathrm{~kJ}...
Air enters the compressor of a cold air-standard Brayton cycle at 100 kpa, 300 k, with a mass flow rate of 6 kg/s. the compressor pressure ratio is 10, and the turbine inlet temperature is 1400 K. For k = 1.4, calculate a. The thermal efficiency of the cycle b. The back work ratio c. The net power developed, in kW d. Reconsider the above with an ideal regenerator.
An ideal Brayton cycle with regeneration is shown below. Note
that from 1 to 6, there is a heat rejection process. The pressure
ratio is 10 and the inlet to the compressor is at 300 K and 100
kPa. The maximum temperature is 1100 K. Use air as the working
fluid, and assume constant properties evaluated at 300
K.
(a) Find the net work output and the cycle efficiency assuming
the effectiveness of the regenerator is 100%
(b) Plot the...
2. Air enters the compressor of a regenerative gas turbine engine at 310 K and 100 kPa, where it is compressed to 900 kPa and 650 K. The regenerator has an effectiveness of 80%and the air enters the turbine at 1400 K. For a turbine isentropic efficiency of 90%, , then: (a) Sketch the T-s diagram of the cycle. (b) Determine the amount of heat transfer in the regenerator (c) Calculate the thermal efficiency of the cycle (d) Determine the...
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