Find the z score that has 80% of its area to the right? Show work
solution
Using standard normal table,
P(Z > z) =80 %
= 1 - P(Z < z) = 0.80
= P(Z < z ) = 1 - 0.80
= P(Z < z ) = 0.20
= P(Z <- 0.84 ) = 0.20
z- score = - 0.84 (using standard normal (Z) table )
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