How does Ohm's law help calculate the charge/mass ratio of an electron such as the experiment by JJ Thomson?
In JJ Thomson experiment we find out the charge/mass ratio by applying electric and magnetic field.
The e/m ratio comes out to be
e/m = E2/2VB2
Where V is the variable potential which we can use to balance charge and mass
The Potential is find out by ohms law.
V = IR
Here is the use of ohms law
thanks
How does Ohm's law help calculate the charge/mass ratio of an electron such as the experiment...
In a fictitious world the Thomson cathode ray experiments found the electron charge to mass ratio to be 9.25×105 C/g. A series of oil drops in the Milikan oil drop experiment were found to have excess charges of 3.73×10-19 C, 4.66×10-19 C and 2.80×10-19 C. What could be the mass of an electron? 1.01×10-25 grams 2.80×10-19 grams 3.73×10-19 grams 5.04×10-25 grams 4.03×10-25 grams
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In 1877 J. J. Thomson measured the charge to mass ratio of the electron and in doing so he neglected the gravitational effects of the earth and the effects of the earth's magnetic field. What errors were thereby introduced?
In 1877 J. J. Thomson measured the charge to mass ratio of the electron and in doing so he neglected the gravitational effects of the earth and the effects of the earth's magnetic field. What errors were thereby introduced?
Imagine an alternate reality. The Thomson cathode ray experiments arrived at a charge to mass ratio, 8.51×106 C/g for the electron. If when Milikan performed the oil drop experiment he found that a series of droplets had excess charges of 3.11×10-19 C, 1.56×10-19 C and 2.08×10-19 C, what could be the mass of an electron?
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