18–45 A house located in Boulder, Colorado (408 N latitude), has ordinary double-pane windows with 6-mm-thick...
18–45 A house located in Boulder, Colorado (408 N latitude), has ordinary double-pane windows with 6-mm-thick glasses and the total window areas are 8, 6, 6, and 4 m2 on the south, west, east, and north walls, respectively. Determine the total solar heat gain of the house at 9:00, 12:00, and 15:00 solar time in July. Also, determine the total amount of solar heat gain per day for an average day in January.
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18–45 A house located in Boulder, Colorado (408 N latitude), has
ordinary double-pane windows with 6-mm-thick...
A 2 ft high x 6 ft wide double-glazed window faces southwest. The window has a frame with width o...
A 2 ft high x 6 ft wide double-glazed window faces southwest. The window has a frame with width of 1.25 in. around the outside edge. The top of the window has a 1.5 ft overhang that extends a great distance on each side of the window. The incident angle is 60 deg, the incident direct irradiation is 120 Btu/hr-ft, and the incident diffuse irradiation is 50 Btu/hr-ft. 1- Compute the shaded area of the frame and glazing on July...
1 2 Calculate the following cooling load components at 18:00 hour of August month for the...
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Calculate the following cooling load components at 18:00 hour of August month for the shown hall: (a) Heat transferred through floor, ceiling and doors. (b) Heat gain due to solar effects. (c) Heat gain through the glass windows. (d) Heat gain due to occupants. (e) The heat gain due to lights. (1) Heat transmitted due to infiltration. (g) The total cooling load. The following data are given: The ceiling height is 3.0 m. The hall has eight glass...
A 2 ft high x 6 ft wide double-glazed window faces southwest. The window has a frame with width of 1.25 in. around the outside edge. The top of the window has a 1.5 ft overhang that extends a great distance on each side of the window. The incident angle is 60 deg, the incident direct irradiation is 120 Btu/hr-ft, and the incident diffuse irradiation is 50 Btu/hr-ft. 1- Compute the shaded area of the frame and glazing on July...
1
2
Calculate the following cooling load components at 18:00 hour of August month for the shown hall: (a) Heat transferred through floor, ceiling and doors. (b) Heat gain due to solar effects. (c) Heat gain through the glass windows. (d) Heat gain due to occupants. (e) The heat gain due to lights. (1) Heat transmitted due to infiltration. (g) The total cooling load. The following data are given: The ceiling height is 3.0 m. The hall has eight glass...
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