Time to review: The following table presents the time taken to review articles that were submitted...
Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than
6 months to review; these are omitted from the table. Consider the data to be a population.
| Time (Months) | Number of Articles |
|---|---|
| −00.9 | 48 |
| −1.01.9 | 15 |
| −2.02.9 | 17 |
| −3.03.9 | 19 |
| −4.04.9 | 11 |
| −5.05.9 | 16 |
(a) Approximate the variance of the times. Round the answer to
at least two decimal places.
The variance is______.
(b) Approximate the standard deviation of the times. Round the answer to at least two decimal places.
The standard deviation is_____.
Homework Answers
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Time to review: The following table presents
the time taken to review articles that were submitted...
Question 6 of 20 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review:...
Question 6 of 20 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Time (Months) Number of Articles 0-0.9 1.0-1.9 2.0 - 2.9 3.0-3.9 4.0 - 4.9 5.0-5.9 Send data to...
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Question 6 of 8 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Number of Articles TA Time (Months) 0-0.9 44 16 1.0-1.9 2.0 - 2.9 3.0-3.9 17 20 4.0-4.9 12...
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An expert reviews a sample of 10 scientific articles (n = 10) and records the following number of errors in each article: 2, 0, 4, 1, 5, 6, 9, 8, 5, and 9. Compute SS, variance, and standard deviation for this sample using the definitional and computational formula. (Round your answers to two decimal places.) SS= 92.9
A manufacturer claims that the mean lifetime, H, of its light bulbs is 48 months. The...
A manufacturer claims that the mean lifetime, H, of its light bulbs is 48 months. The standard deviation of these lifetimes is 6 months. Fifty bulbs are selected at random, and their mean lifetime is found to be 49 months. Can we conclude, at the 0.1 level.of signficance, that the mean lifetime of light bulbs made by this manufacturer differs from 48 months? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at least...
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X Incorrect. In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes at 34kV. The times, in minutes, are as follows: 0.22, 0.73, 0.94, 1.33, 2.89, 3.30, 4.29, 4.61, 4.81, 6.54, 7.36, 8.06, 8.38, 12.01, 31.98, 32.44, 33.77, 36.10, and 72.09. Calculate the sample mean and sample deviation of the breakdown data. Round your answers to 2 decimal places. Mean = || 14.27 minutes X Standard Deviation = T18.73 minutes
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An investor owns a portfolio consisting of two mutual funds, A and B, with 60% invested in A. The following table lists the inputs for these funds. Fund B Fund A 30 Measures Expected value Variance Covariance 24 49 87 36 a. Calculate the expected value for the portfolio return. (Round your answer...
Tommy Wait, a minor league baseball pitcher, is notorious for taking an excessive amount of time...
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A professor records the time (in minutes) that it takes 16 students to complete an exam....
A professor records the time (in minutes) that it takes 16 students to complete an exam. Compute the SS, the variance, and the standard deviation assuming the 16 students constitute a population and assuming the 16 students constitute a sample. (Round your answers for variance and standard deviation to two decimal places.) 50 51 39 41 29 33 48 21 14 25 24 38 27 40 44 32
In a country, the mean time served by prisoners released from prison for the first time...
In a country, the mean time served by prisoners released from prison for the first time is 34.4 months. Assume the standard deviation of the times served is 15.3 months. Let x denote time served to first release by a prisoner. Complete parts (a) through (e) below. a. Find the standardized version of x. b. Find the mean and standard deviation of the standardized variable. c. Determine the z-scores for prison times served of 77.9 months and 26.3 months. Round...
Question 6 of 20 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Time (Months) Number of Articles 0-0.9 1.0-1.9 2.0 - 2.9 3.0-3.9 4.0 - 4.9 5.0-5.9 Send data to...
Question 6 of 8 (1 point) Attempt 1 of Unlimited 3.2 Section Exercise Time to review: The following table presents the time taken to review articles that were submitted for publication to a particular journal during a recent year. A few articles took longer than 6 months to review; these are omitted from the table. Consider the data to be a population. Number of Articles TA Time (Months) 0-0.9 44 16 1.0-1.9 2.0 - 2.9 3.0-3.9 17 20 4.0-4.9 12...
A manufacturer claims that the mean lifetime, H, of its light bulbs is 48 months. The standard deviation of these lifetimes is 6 months. Fifty bulbs are selected at random, and their mean lifetime is found to be 49 months. Can we conclude, at the 0.1 level.of signficance, that the mean lifetime of light bulbs made by this manufacturer differs from 48 months? Perform a two-tailed test. Then fill in the table below. Carry your intermediate computations to at least...
X Incorrect. In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes at 34kV. The times, in minutes, are as follows: 0.22, 0.73, 0.94, 1.33, 2.89, 3.30, 4.29, 4.61, 4.81, 6.54, 7.36, 8.06, 8.38, 12.01, 31.98, 32.44, 33.77, 36.10, and 72.09. Calculate the sample mean and sample deviation of the breakdown data. Round your answers to 2 decimal places. Mean = || 14.27 minutes X Standard Deviation = T18.73 minutes
An investor owns a portfolio consisting of two mutual funds, A
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