Question

A study of the career paths of hotel general managers sent questionnaires to an SRS of...

A study of the career paths of hotel general managers sent questionnaires to an SRS of 300 hotels belonging to major U.S. hotel chains. There were 183 responses. The average time these 183 general managers had spent with their current company was 10.35 years. (Take it as known that the standard deviation of time with the company for all general managers is 1.4 years.)

(a) Find the margin of error for an 80% confidence interval to estimate the mean time a general manager had spent with their current company: ______ years

(b) Find the margin of error for a 99% confidence interval to estimate the mean time a general manager had spent with their current company: ______ years

(c) In general, increasing the confidence level _________ the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the quotes.)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ans:

a)z value for 80% confidence level=1.282

Margin of error=1.282*(1.4/sqrt(183))=0.133

b)z value for 99% confidence level=2.576

Margin of error=2.576*(1.4/sqrt(183))=0.267

c)In general,increasing the confidence level INCREASES the margin of error (width) of the confidence interval

Add a comment
Know the answer?
Add Answer to:
A study of the career paths of hotel general managers sent questionnaires to an SRS of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • (1 point) A study of the career paths of hotel general managers sent questionnaires to an...

    (1 point) A study of the career paths of hotel general managers sent questionnaires to an SRS of 210 hotels belonging to major U.S. hotel chains. There were 96 responses. The average time these 96 general managers had spent with their current company was 12.98 years. Take it as known that the standard deviation of time with the company for all general managers is 4.3 years. Give your answers to at least 2 decimal places, and use at least 3...

  • A study of the career paths of hotel general managers sent questionnaires to an SRS of...

    A study of the career paths of hotel general managers sent questionnaires to an SRS of 160 hotels belonging to major U.S. hotel chains . There were 81 responses. The average time these 81 general managers had spent with their current company was 11.78 years. (Take it as known that the standard deviation of time with the company for all general managers is 3.2 years) a. Calculate a 99.5% confidence interval for the mean numbers of years that general managers...

  • A study of the career paths of hotel general managers sent questionnaires to a random sample...

    A study of the career paths of hotel general managers sent questionnaires to a random sample of 97 hotels belonging to major U.S. hotel chains. The average time these 97 general managers had spent with their current company was 12.75 years. (Take it as known that the standard deviation of time with the company for all general managers is 1.8 years.) (a) Find the bound for an 80% confidence interval to estimate the mean time a general manager had spent...

  • 10. 0/10 points Previous Answers YMSStat2 10..013. My A study of the career paths of otel...

    10. 0/10 points Previous Answers YMSStat2 10..013. My A study of the career paths of otel general managers sent questionnaires to an SRS of 160 hotels belonging to major U.S. hotel chains. There were 109 responses. The average time these 109 general managers had spent with their current company was 11.5 years. How large a sample of hotel managers would be needed to estimate the mean within 1.08 year with 80% confidence? (Take it as known that the standard deviation...

  • Entered Answer Preview Result Message -2009.11, 2009.11 -2009.11, 2009.11 incorrect Your answer isn't a number (it...

    Entered Answer Preview Result Message -2009.11, 2009.11 -2009.11, 2009.11 incorrect Your answer isn't a number (it looks like a list of numbers) 41686.9 41686.9 correct 45705.1 45705.1 correct At least one of the answers above is NOT correct. (1 point) Starting salaries of 95 college graduates who have taken a statistics course have a mean of $43,696. Suppose the distribution of this population is normal and has a standard deviation of $10,819. Using a 93% confidence level, find both of...

  • Problem 2- Confidence Interval The average cost per night of a hotel room in New York...

    Problem 2- Confidence Interval The average cost per night of a hotel room in New York City is $273 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65. T- statistic is 2.015. a. b, c. With 95% confidence, what is the Margin of Error(ME)? what is the 95% confidence interval estimate of the population mean? Two years ago the average cost of a hotel room in New...

  • The average cost per night of a hotel room in New York City is $273 (SmartMoney,...

    The average cost per night of a hotel room in New York City is $273 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65. T- statistic is 2.015. a. With 95% confidence, what is the Margin of Error(ME)? b. What is the 95% confidence interval estimate of the population mean? c. Two years ago the average cost of a hotel room in New York City was $229....

  • The average cost per night of a hotel room in New York City is $263 (SmartMoney,...

    The average cost per night of a hotel room in New York City is $263 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $50. a. With 95% confidence, what is the margin of error? Round your answer to the nearest dollar. b. What is the 95% confidence interval estimate of the population mean? Round your answers to the nearest dollar. c. Two years ago the average cost...

  • The average cost per night of a hotel room in New York City is $269 (SmartMoney,...

    The average cost per night of a hotel room in New York City is $269 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $55. a. With 95% confidence, what is the margin of error? Round your answer to the nearest dollar. $ b. What is the 95% confidence interval estimate of the population mean? Round your answers to the nearest dollar. to c. Two years ago the...

  • (1 point) A market research firm supplies manufacturers with estimates of the retail sales of their...

    (1 point) A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores. Marketing managers are prone to look at the estimate and ignore sampling error. An SRS of 27 stores this year shows mean sales of 64 units of a small appliance with a standard deviation of 7 units. During the same point in time last year, an SRS of 25 stores had mean sales of 57.21 units, with standard...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT