Under typical atmospheric conditions, there is an electric field near the earth's surface, directed downward, with a magnitude of 100 V/m. |
Part A If we say that the potential at the earth's surface is 0 V, what is the potential 1.5 kmabove the surface? |
The potential difference between two point and in a electric field is given by the line integral given below
where is a small line element along the path of integration and is the angle between and . In our problem is because is downward and is upward. In our problem point is earth surface where potential is zero, so . Also in our problem is constant, so we can take it out of integral. So the potential at point is given by
where is the distance between point and .
In our problem and . So the potential at point , above the earth surface is given by
So, the potential above the earth surface is .
Under typical atmospheric conditions, there is an electric field near the earth's surface, directed downward, with...
Under normal atmospheric conditions, there exists a weak electric field near the earth's surface, pointing vertically downward, whose value is 150 N/C. Find the necessary charge on a 2.70 gram ping-pong ball so that the ball could levitate' in this field. In other words, the upward electrical force would just balance the downward gravitational force. Would the acquired charge need to be positive or negative?
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Under normal atmospheric conditions, there exists a weak electric field near the earths surface, pointing vertically downward, whose value is 150 N/C. Find the necessary charge on a 2.70 gram ping-pong ball so that the ball could "levitate' in this field. In other words, the upward electrical force would just balance the downward gravitational force. Would the acquired charge need to be positive or negative?
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