Determine the better reducing agent under standard conditions: H2 vs I2 According to the standard reduction...
Determine the better reducing agent under standard conditions:
H2 vs I2
According to the standard reduction table, I2 +2e > 2I- has a standard reduction potential of 0.54. I'm confused because I2 is a reactant in the table instead of a product. Do both I2 and 2I- have a standard reduction potential of 0.54? Or is I2's standard reduction potential = negative 0.54 ?
Homework Answers
reducing agent = which involves in oxidation readily can acts as strong reducing agent.
The elements/ions involves in oxidation or reduction can be decided by comparing with SRP values.
Greater the SRP value that ion/element involves in reduction.lesser the SRP values involves in oxidation.
Standard reduction potential(SRP):
2H+ + 2 e− ---> H2(g) , E0 = 0.0 V
I2(s) + 2 e− ----> 2I− , E0 = +0.54 v
Hence, SRP of Hydrogen is less than iodine.so that, H2 involves in oxidation,act as reducing agent.compared to I2.
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Determine the better reducing agent under standard
conditions:
H2 vs I2
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