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Methylene chloride has a melting point of - 94.8°C, a boiling point of 40.0°C, a specific...

Methylene chloride has a melting point of - 94.8°C, a boiling point of 40.0°C, a specific heat of 1.21 J/g *K for the solid and liquid, and 0.608 J/g*K for the gas. The heats of fusion and vaporization are ΔHfus of 73.40 J/g, and ΔHvap of 334.35 J/g respectively. Determine how many joules of energy are needed to heat 40 grams of methylene chloride from -171.4 ° F to 333 K.   Draw out and label your heating curve. This will require a total of 6 steps.
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Answer #1

ANS:

q = m·ΔHf
where
q = heat energy
m = mass
ΔHf = heat of fusion

Temperature is not anywhere in the equation because it doesn't change when matter changes state. The equation is straightforward, so the key is to make sure you're using the right units for the answer.

To get heat in Joules:
q = (25 g)x(334 J/g)
q = 8350 J
It's just as easy to express the heat in terms of calories:
q = m·ΔHf
q = (25 g)x(80 cal/g)
q = 2000 cal
Answer: The amount of heat required to melt 40 grams of CH3Cl is 8,350 Joules or 2,000 calories.

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