Two masses are hanging from the ends of a 1m bar. Where is the balance point of the system? m1 is 1 kg, m2 is 3 kg
Xcm = (m1x1 + m2x2)/(m1+m2)
= 1(0) + 3(1) /(3+1) = 0.75 m
= 75 cm
The mass 1 kg is at the left most end and the 3kg mass is the right most end.
Answer is 75 cm.
Two masses are hanging from the ends of a 1m bar. Where is the balance point...
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