Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sampling error is 5% or less?
Ans:
n=400
z(0.31)=(0.31-0.36)/SQRT(0.36*(1-0.36)/400)=-2.083
z(0.41)=(0.41-0.36)/SQRT(0.36*(1-0.36)/400)=2.083
P(0.31<p-hat<0.41)=P(-2.083<z<2.083)=P(z<2.083)-P(z<-2.083)
=0.9814-0.0186=0.9628
Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh...
Suppose the American Kennel Club estimates that 36% of households in U.S. have a pembroke welsh corgi. A random sample of 400 households is taken. A) What is the probability that the sample proportion is more than 40%? B) what is the probability that the sample proportion is within .04 of P? C) what is the probability the sampling error is 5% or less?
Suppose the American Kennel Club estimates that 36% of households in U.S. have a Pembroke Welsh Corgi. A random sample of 400 households is taken. What is the probability the sample proportion is within .03 of P? Question 14 options: 1) .9044 2) 1 3) 0 4) .7887
(4) According to a survey conducted by Harrah's Home Testing Institute, adults from 50% of U.S. households have gambled in a casino at some time in their life (American Demographics, October 1993). Assume that this percentage is true for the current population of adults from all U.S. households. A random sample of 400 U.S. households is selected. (a) Using normal approximation to find the probability that at least 320 of the 400 selected houscholds have gambled in a casino at...
In a large population, 67% of the households have cable tv. A simple random sample of 81 households is to be contacted and the sample proportion computed. What is the probability that the sampling distribution of sample porportions is less than 63%?
please answer all! its actually shorter than you think!
I. In the U.S., 65.2% of households own their own home. Consider a random sample of 11 U.S. households. Find the probability that exactly six own their own home by hand 2, For the situation in #1: a. Find the probability that less than 10 of the 11 randomly chosen U.S. households own their own home by hand. 3. For the situation in #1, how many U.S. households out of 11...
According to the Federal Communications Commission, 70% of all U.S. households have cable television. Erica selects a random sample of 1,000 households in Dupage Country, what is the probability of obtaining a random sample of at least 734 households with cable from a sample size 1,000?
1- In a large population, 67% of the households have cable tv. A simple random sample of 81 households is to be contacted and the sample proportion computed. What is the probability that the sampling distribution of sample porportions is less than 63%?
Exercise 1: Suppose we wish to assess whether more than 60% of all U.S. households in a particular income class bought life insurance last year. An insurance survey is based on 100 randomly selected U.S. households in the income class and 64 bought life insurance last year. Assuming p = 0.60, 1) What the mean for the sampling distribution of proportions? 2) What is the standard deviation for the sampling distribution of proportions? 3) What is the probability of observing...
According to Nielsen Media Research, the average number of hours of TV viewing per household per week in the United States is 50.4 hours. Suppose the standard deviation is 11.8 hours and a random sample of 42 U.S. households is taken. A. What is the probability that the sample average is more than 52 hours? B. What is the probability that the sample average is less than 47.5 hours? C. What is the probability that the sample average is less than 40 hours?...
According to the Federal Communications Commission, 70% of all U.S. households have vcrs. In a random sample of 15 households, what is the probability that the number of households with vcrs is between 10 and 12, inclusive? A) 0.2061 B) 0.4053 C) 0.5948 D) 0.7329