Suppose the average golfer drives the ball around 232.23 yards with a standard deviation of 5.96. However, when given a new type of driver, every observation in the dataset is multiplied by 1.03. What is the new mean?
Suppose the average golfer drives the ball around 232.23 yards with a standard deviation of 5.96....
Question 8 (1 point Suppose that a police officer measured the speed of cars on a highway for an hour. The average speed of the cars was 70.5 and the standard deviation was 4.86. However, since the radar gun was biased, 4 is added to every observation in the dataset. What will the new mean be? 1) 74.5 2) 17.62 3) 4) 282 5) 70.5 Total enrollment in the Kalamazoo Public Schools have a mean and standard deviation of 11/485.2...
Nancy, a golfer, claims that her average driving distance is 253 yards. During a practice session, Nancy has a sample driving distance mean of 229.6 yards based on 18 drives. At the 2% significance level, does the data provide sufficient evidence to conclude that Nancy's mean driving distance is less than 253 yards? Accept or reject the hypothesis given the sample data below. H0:μ=253 yards; Ha:μ<253 yards α=0.02 (significance level) z0=−0.75 p=0.2266 Select the correct answer below: Do not reject...
4) 282 5) 70.5 Question 9 (1 point) Total enrollment in the Kalamazoo Public Schools have a mean and standard deviation of 11,485.2 and 19.2, respectively. The district expects growth in the next five years, so every observation in the dataset is multiplied by 1.2. What will the new mean be? 1) 11,485.2 2) 11,486.4 3) 1.2 4) 9,571 5) 13,782.24 Suppose that the average and standard deviation of the tine for speeding on a particular highway are 111.12 and...
Does it matter what kind of tee a golfer places the ball on? A company that manufactures golf tees claims that the thinner shaft and smaller head of their tee will lessen resistance and drag, reducing spin and allowing the ball to travel farther. A golfing research facility compared the distance travelled by golf balls hit off regular wooden tees to those hit off the new tees. All the balls were struck by the same golf club using a robotic...
Suppose the average grade in this class is 85 with standard deviation 2.50. a) If each grade is increased by 5 points, what are the new mean and standard deviation? b) If each grade is increased by 5%, what are the new mean and standard deviation?
(1 point) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 235 yards on average. Suppose a random sample of 131 golfers was collected and their sample mean driving distance was 234.4 yards. The population standard deviation is 49.9. Use a...
4) A population has a mean of μ = 55 and a standard deviation of σ = 15. a) If 3 points were added to every score in the population, what would be the new values for the mean and standard deviation? b) If every score in the population were multiplied by 2, then what would be the new values for the mean and standard deviation?
5. A professional golfer executes hundreds of shots every day and his average drive is 295 yards with a standard deviation of seven yards. This is based on hitting and documenting each individual drive a) If his drive has to travel 310 yards in the air in order to clear the 2nd water hazard, what is the probability that he can hit a drive over the 2nd water hazard? *Do not use values from your calculator – Use the table...
A golfer claims that his average golf score at the course he plays regularly is less than 90. A random sample of 35 rounds of golf was selected and the scores were recorded. Assume that the standard deviation for the population of scores for this golfer is 3.4 and the true population mean for scores for this golfer is 88.2. Using α = 0.05, beta equals ________.A) 0.0694B) 0.0944C) 0.1292D) 0.1895
(6 points) Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 250 yards on average. Suppose a random sample of 140 golfers be chosen so that their mean driving distance is 248 yards. The population standard deviation is 44.7. Use a...