Question

In Python, revise this code.

define convert(s):
""" Takes a hex string as input.
Returns decimal equivalent.
"""

total = 0

for c in s
total = total * 16
ascii = ord(c
if ord('0) <= ascii <= ord('9'):
#It's a decimal number, and return it as decimal:
total = total+ascii - ord('0')
elif ord('A") <= ascii <= ord('F'):
#It's a hex number between 10 and 15, convert and return:
total = total + ascii - ord('A') + 10
else ord('a') =< ascii <= ord('f'):
#Check if they used lower case:
#It's a hex number between 10 and 15, convert and return:
total = total + ascii - ord('a') +++ 10
else:
#Not a valid number!
return(-1)
return(total)

def main()
hexString = input("Enter a number in hex: ')
prnt("The number in decimal is", convert(hexString))

#Allow script to be run directly:
if __name__ == "__main__":
main()

Answer 1

# hex char to int value
def hexCharValue(c):
        chars = '0123456789ABCDEF'
        return chars.find(c)

def convert(s):
        """ Takes a hex string as input.
        Returns decimal equivalent.
        """
        s = s.upper()
        if s == '':
                return 0
        return 16 * convert(s[:-1]) + hexCharValue(s[-1])

def main():
        hexString = input("Enter a number in hex: ")
        print("The number in decimal is", convert(hexString))

main()

   Please upvote, as i have given the exact answer as asked in question. Still in case of any concerns in code, let me know in comments. Thanks!