Please solve in java
Write a program that serves as a simple calculator. The program should ask the user for a number, an operator, and then a second number. The operator should be either '+', '-', 'x', or '/'. The program should then report the answer to the problem. Use a switch statement, not an if statement. You'll need to read the operator as a String and compare it using Strings, as you did in 4.1.
Turn in your source code and your output. A single output is sufficient.
If you have any doubts, please give me comment...
import java.util.Scanner;
public class SimpleCalculator{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter first number: ");
int n1 = in.nextInt();
System.out.print("Enter an operator: ");
String op = in.next();
System.out.print("Enter second number: ");
int n2 = in.nextInt();
switch(op){
case "+":
System.out.println("Addition of "+n1+" and "+n2+" = "+(n1+n2));
break;
case "-":
System.out.println("Subtraction of "+n1+" and "+n2+" = "+(n1-n2));
break;
case "x":
System.out.println("Multiplication of "+n1+" and "+n2+" = "+(n1*n2));
break;
case "/":
System.out.println("Division of "+n1+" and "+n2+" = "+(n1/n2));
break;
default:
System.out.println("Invalid operator!");
}
}
}
Please solve in java Write a program that serves as a simple calculator. The program should...
Simple calculator program. The program should ask the user for a number, an operator, and then a second number. The operator should be either '+', '-', 'x', or '/'. The program should then report the answer to the problem. Use a switch statement, not an if statement. Note that "operator" is a reserved word in C++, so you cannot use it as a variable name. Use double variables and setprecision(2).
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