If the mean is 96.78, mu is 98, standard deviation is 29.11 and n= 90, how do I find the p value
If the mean is 96.78, mu is 98, standard deviation is 29.11 and n= 90, how...
A population has a mean mu= 72 and a standard deviation sigma= 6. Find the mean and standard deviation of a sampling distribution of sample means with sample size n= 36.
Find the mean and standard deviation for each binomial random variable: a. n = 52, π = .80 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean 41.6 Standard deviation b. n = 90, π = .60 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) Mean 54 Standard deviation c. n = 42, π = .75 (Round your mean value to 2 decimal places and standard...
The mean and standard deviation of a random sample of n measurements are equal to 34.1 and 3.5, respectively. a. Find a 90% confidence interval for mu if nequals64. b. Find a 90% confidence interval for mu if nequals256. c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the sample size while holding the confidence coefficient fixed?
1. Giving a normal distribution with mean mu=35 and standard deviation sigma = 10 where the probability that x is less than x0 is p0 = 0.95 what is the value for x0. 2.Giving a normal distribution with mean mu=35 and standard deviation sigma =10 where the probability that x is greater than x0 is 0.10. 3. Giving a normal distribution with mean mu=40 and standard deviation sigma = 10 where the probability that x0<x<x1 = 0.9. What is the...
Assume that IQ's follow a Normal distribution with a mean mu=100 and standard deviation sigma=16. What is the probability that no more than 5 people in a random sample of size n=9 have IQ's between 90 and 110?
Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n equals 70 , p equals 0.3 The mean, mu , is nothing . (Round to the nearest tenth as needed.)
A population has a mean of 400 and a standard deviation of 90. Suppose a sample of size 100 is selected and x with bar on top is used to estimate mu. What is the probability that the sample mean will be within +/- 3 of the population mean (to 4 decimals)? (Round z value in intermediate calculations to 2 decimal places.) What is the probability that the sample mean will be within +/- 14 of the population mean (to...
Assume the random variable x is normally distributed with mean mu equals80 and standard deviation sigma equals 5. Find the indicated probability. P(68less thanxless than71) P(68less thanxless than71)equals nothing (Round to four decimal places as needed.)
Find the mean and standard deviation for each binomial random variable: a. n = 36, ππ = .75 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) b. n = 75, ππ = .55 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.) c. n = 26, ππ = .90 (Round your mean value to 2 decimal places and standard deviation to 4 decimal places.)
In a certain distribution, the mean is 90 with a standard deviation of 4. Use Chebychev's inequality to tell the probability that a number lies between 82 and 98. The probability a number lies between 82 and 98 is at least .