An 80 kg object is dropped from rest from a height of 25 meters above the...
An 80 kg object is dropped from rest from a height of 25 meters above the ground. Use the concept of energy conservation to find its speed when it is 10 meters above the ground.
Homework Answers
Using law of conservation of energy,
0.5 mv^2 = mg (h1 - h2)
Velocity, v = sqrt(2 g (h1 - h2))
V = sqrt(2 x 9.8 x (25 - 10)) = 17.2 m/s
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