Question

On a compact disc (CD), music is coded in a pattern of tiny pits arranged in a track that spirals outward toward the rim of the disc. As the disc spins inside a CD player, the track is scanned at a constant linear speed of v = 1.25 m/s. Because the radius of the track varies as it spirals outward, the angular speed of the disc must change as the CD is played. Let's see what angular acceleration is required to keep v constant. The equation of a spiral is r(θ)=r0+βθ, where r0 is the radius of the spiral at θ = 0 and β is a constant. On a CD, r0 is the inner radius of the spiral track. If we take the rotation direction of the CD to be positive, β must be positive so that r increases as the disc turns and θ increases.When the disc rotates through a small angle dθ, the distance scanned along the track is ds=rdθ. Using the above expression for r(θ), integrate ds to find the total distance s scanned along the track as a function of the total angle θ through which the disc has rotated. When the disc rotates through a small angle dθ, the distance scanned along the track is ds=rdθ. Using the above expression for r(θ), integrate ds to find the total distance s scanned along the track as a function of the total angle θ through which the disc has rotated. Since the track is scanned at a constant linear speed v, the distance s found in part A is equal to vt. Use this to find θ as a function of time. There will be two solutions for θ; choose the positive one.

Answer 1