the rate contant, k, for second order rection is in the unit of: a) M/s b)...
s ) at 650 K and a 18. For a certain second order reaction, the rate constant has a value of 0.22 ( M value of 23 at 800 K. Calculate the activation energy (in kJ/mole) for this reaction. (A) 84 (B) 134 (C) 42 (D) 107 (E) 63
1. A reaction is second order in[A] and second-order in [B]: Rate,=K[A]^2[B]^2. what are the units of k for this reaction? If the concentration of air decreases by a factor of 2 and the concentration of b increases by a factor of 5 what happens to the rate? 2. for the forward reaction 2NO+Cl2=>2NOCl. determine the rate(m/s)for experiment #4 given [NO]°(M)=0.40M and [Cl2]°z(M)=0?20M. Rate? 3.The following data were collected over time for the forward reaction 2NO2=>2NO+O2 ( 1/[NO2]=100 at 0...
A second order reaction A->B begins at 10:45 AM with [A]= 1.25 M. If the rate constant k= 0.032M^-1 s^-1, at what clock time does [A]= 0.05 M?
Consider the following rection and rate law:\(2 A+3 B+C \rightarrow 4 D\)rate \(=\mathrm{k}[\mathrm{A}][\mathrm{C}]^{3}\)If you were to increase the amount of \(\mathrm{A}\) by 16 , increase the amount of \(\mathrm{B}\) by 10 , and cut the amount of \(\mathrm{C}\) in half, what would that do to the rate of the reaction?new rate \(=\quad \mathrm{x}\) old rate.
The rate constant for this second-order reaction is 0.430 M-'.s at 300 °C. A- products How long, in seconds, would it take for the concentration of A to decrease from 0.670 M to 0.310 M? 1 = 6.355 Incorrect Calculate the rate constant, k, for a reaction at 56,0 °C that has an activation energy of 88.6 kJ/mol and a frequency factor of 6.85 x 10's-1 k= 2.2188 SI Incorrect
Submit What is the rate for the second order reaction AProducts when [A] 0.201 M? (k M/s 4 6 0 x 100
If the rate law for the reaction2A + 3B ? productsis first order in A and second order in B, then the rate law is rate = ________________.a. k [A] [B]b. k [A]2 [B]3c. k [A] [B]2d. k [A]2 [B]e. k [A]2 [B]2
For a first-order reaction, the half-life is constant. It depends only on the rate constant k k and not on the reactant concentration. It is expressed as t1/2=0.693k t 1 / 2 = 0.693 k For a second-order reaction, the half-life depends on the rate constant and the concentration of the reactant and so is expressed as t1/2=1k[A]0. A certain first-order reaction (A→products A → p r o d u c t s ) has a rate constant of 9.30×10−3...
(b) Determine the values of K and k for the following second order system so that the maximum overshoot in unit response is 25% and peak time is 2 sec. K G(s) (Note: Peak Overshoot = e-Sn//1- and Peak Time= / 0a) (5 Marks) s2+Kks+K
The following reaction is second order in [A] and the rate constant is 0.025 M-1s-1: The concentration of A was 0.65 M at 33 s. The initial concentration of A was ________ M. Select one: a. 0.24 b. 1.2 � 10-2 c. 0.27 d. 2.4 e. 1.4