A solution is 0.0045 M in both Pb2+ and Ca2+. Solid Na2SO4 is added to precipitate the sulfates. What concentration of SO42‒ is needed to precipitate as much of the Pb2+ without precipitating the Ca2+? Ksp(PbSO4) = 1.6 × 10‒8, Ksp(CaSO4) = 2.4 × 10‒4
A solution is 0.0045 M in both Pb2+ and Ca2+. Solid Na2SO4 is added to precipitate...
Solid sodium sulfate, Na2SO4, is added slowly to a solution that is 1.0 x 10-4 in both Ba2+ and Pb2+ until [SO42-] reaches 1.0 x 10^-4 M. Would either BaSO4 (Ksp = 1.1 x 10^-10) or PbSO4 (Ksp = 1.7 x 10^-8) precipitate under these conditions?
QUESTION 21 A solution is 0.012 Min Pb(NO3)2 and 0.20 Min Sr(NO3)2. Solid Na2SO4 is added until a precipitate just begins to form. The precipitate is and the concentration of sulfate ion at this point is Ksp for PbSO4 is 1.8 x 10-8 and for SrS04 is 2.8 x 10-7 PbSO4: 1.5 10 M SrS04; 1.4 x 10-6M PbSO4; 6.3 * 10 M "SrS04; 8.3 x 10-?M S-S04:2.6 x 10-7M
Solid sodium iodide is slowly added to a solution that is 0.0050 M Pb2+ and 0.0050 M Ag+. What is the concentration of silver when the lead (II) iodide just begins to precipitate? [Ksp (Pbi2) = 1.4 × 10–8; Ksp (Agi) = 8.3 × 10–17] Please show all work
Questions: 1. Calculate the Ksp for PbBr2 if its molar solubility is 2.14 x 10-2 M at 25°C. 2. Calculate the molar solubility of CaF2 (Ksp = 4.0 x 10-11) in a 0.025 M NaF solution. 3. Solid sodium sulfate, Na2SO4, is added slowly to a solution that is 1.0 x 10-4 in both Ba2+ and Pb2+ until [SO42-] reaches 1.0 x 10-4 M. Would either BaSO4 (Ksp = 1.1 x 10-10) or PbSO4 (Kop -1.7 x 10-8) precipitate under...
9. Solid NaF is slowly added to a solution that is 0.0100 M in Ca2+ and 0.0100 M in Pb2+. Which solid CaF2 or PbF2, will precipitate first?
A solution contains 0.040 M of Na2SO4 and 0.050 M of NaIO3. Another solution of Ba2+ is added to the first solution.( You must accept that the original solution does not include HSO-4). a) Which of the Baryum salts precipitate firstly? b) Calculate the Ba2+ concentration while the first precipitate is occuring. c) While the more dissolved precipitate is precipitating, what is the concentration of anion which forms the less dissolved Baryum salt ? Ba(IO3) Ksp= 1.57x10-9 BaSO4 Ksp= 1.1x10-10
A solution of Na2SO4 is added dropwise to a solution that is 1.1×10−2 M in Ba2+ and 1.1×10−2 M in Sr2+. 1. What concentration of SO2−4 is necessary to begin precipitation? (Neglect volume changes. BaSO4:Ksp=1.1×10−10; SrSO4:Ksp=3.2×10−7.) 2. What is the concentration of SO2−4 when the second cation begins to precipitate?
Consider a solution that is 1.3×10−2 M in Ba2+ and 1.8×10−2 M in Ca2+. Ksp(BaSO4)=1.07×10−10 Ksp(CaSO4)=7.10×10−5 *Part A: If sodium sulfate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? If sodium sulfate is used to selectively precipitate one of the cations while leaving the other cation in solution, which cation will precipitate first? A) Ba2+ (ANSWER) B) Ca2+ *Part B: What minimum concentration of Na2SO4 is required...
how much Sr2+ will precipitate if 10^-3 mole Na2SO4 added per litter of solution. How much SO42- and Sr2+ remain after precipitation. Given that 10-4 mole/L of Sr2+ and 10-4 of SO42- are originally present and that pKso = 7.8 for SrSO4 (s)
A solution of Na2SO4 is added dropwise to a solution with 0.020 M Ba2+ and 0.020 M Sr2+. (for BaSO4, Ksp = 1.1x10–10 and for SrSO4, Ksp = 3.2x10–7) (a) What precipitate will form first? Why? (b) What concentration of SO4 2– in the solution is necessary to begin precipitation? (neglect any volume change)