The 98% confidence interval about the proportion of applicants who were accepted to a medical school in 2011 is (0.455, 0.464).
a) (2 points) Identify the point estimate for the proportion of applicants who were accepted to a medical school.
b) (2 points) Identify the margin of error for the proportion of applicants who were accepted to a medical school.
Confidence interval in terms of sample proportion and margin of error E is represented as
( - E , + E)
Comparing these two confidence intervals we get,
- E = 0.455 and + E = 0.464
Adding two equations
2 = 0.455 + 0.464
= 0.4595
Point estimate of p = = 0.4595 ( = 0.460 Rounded to three decimals)
b)
Put value of is equation + E = 0.464 and solve for E
0.4595 + E = 0.464
E = 0.0045 ( = 0.005 rounded to three decimals)
The 98% confidence interval about the proportion of applicants who were accepted to a medical school...
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