There are six cans of root beer, four cans of ginger ale, and ten cans of...
There are six cans of root beer, four cans of ginger ale, and ten cans of cola in a cooler. If two cans are drawn in succession, without replacement, find the probability that the first is root beer and the second is not root beer. Report your answer as a fraction in the lowest terms or as a decimal to the nearest thousandth, Please show me work and formula used thanks so much!
Homework Answers
Total beers = 6 + 4 + 10 = 20
Hence,
P(First is root beer and second is not root beer)
= P(1st root beer) * P(Second not root beer | 1st root beer)
= (6/20) * (14/19)
= 21/95
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