I will be calculating the population mean number of times adults eat during the day. I...
I will be calculating the population mean number of times adults eat during the day. I asked 10 adults at work to see how many times a day they normally eat. The responses were (2,3,3,2,3,3,4,5,3,3). Please calculate a 80% confidence interval for the number of meals eaten a day by adults.
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I will be calculating the population mean number of times adults
eat during the day. I...
I want to estimate the population mean number of times that adults go to the movies...
I want to estimate the population mean number of times that adults go to the movies a year. In this prompt, I spoke to 12 different people to find out how many times a year they go to the movies. In this survey, I found that these selected people visited the movies 3,5,2,4,4,2,1,3,4,7,0,1 times a year. Calculate a 90% confidence interval for the population mean.
I want to estimate the population mean number of times that adults go to the movie...
I want to estimate the population mean number of times that adults go to the movie each week. I spoke with seven people I know and found that they went out 2, 0, 1, 5, 0, 2, and 3 times last week. I want to calculate an 80% confidence interval for the population mean. Assume a random sample was chosen, which is required to determine a confidence interval.
the population proportion of people who eat Mcdonalds 3 times per week is 0.15, 180 adults...
the population proportion of people who eat Mcdonalds 3 times per week is 0.15, 180 adults were asked how many times they eat mcdonalds per week. 15 out of 180 people sampled ate mcdonalds 3 times per week. test the hypothesis at 0.25 level. assume a random sample
I believe that the number of adults who eat beef on the 4th of July in...
I believe that the number of adults who eat beef on the 4th of July in Texas is greater than the number of adults who eat beef on the 4th of July in California. In two independent polls, I find that 420 out of 500 Texans ate beef on the 4th of July, and 380 out of 500 Californians ate beef on the 4th of July. Please test with a 95% confidence interval. Can anyone help me solve this step...
A sociologist wants to know the average number of times US families eat their evening meal...
A sociologist wants to know the average number of times US families eat their evening meal at home together each week. Data was collected from 50 random families. The sample mean is 3.8 meals per week with a sample standard deviation of 2.5. Construct a 95% confidence interval to estimate the population mean. Then, state this interval below within an interpretive sentence tied to the given context. Redo #19, only this time assume the value $2.5 is the population standard deviation. Then, state this interval...
A fast food restaurant executive wishes to know how many fast food meals adults eat each...
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 90%90% confidence interval with an error of no more than 0.070.07. A consultant has informed them that a previous study found the mean to be 7.47.4 fast food meals per week and found the variance to be 0.810.81. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next...
A researcher is interested in finding a 98% confidence interval for the mean number of times...
A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 126 students who averaged 34.8 texts per day. The standard deviation was 18.7 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution and texts. b. With 98% confidence the population mean number of texts per day is between c. If many groups of 126...
A researcher is interested in finding a 90% confidence interval for the mean number of times...
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 112 students who averaged 26.7 texts per day. The standard deviation was 24.9 texts. If many groups of 112 randomly selected members are studied, then a different confidence interval would be produced from each group. About _____ percent of these confidence intervals will contain the true population number of texts per day and about _____...
A researcher is interested in finding a 95% confidence interval for the mean number of times...
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 141 students who averaged 25.7 texts per day. The standard deviation was 21.2 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a tv distribution. 0 and b. With 95% confidence the population mean number of texts per day is between texts. c. If many groups of 141...
Michelle is brought in by a provider to determine the number of times per day their...
Michelle is brought in by a provider to determine the number of times per day their customers interact with their smartphone. You take a random sample of 20 customers and find the mean average number of interactions to be 45 times per day with a sample standard deviation of 8. A. Construct a 95% confidence interval (to 2 decimal places) estimate for the population mean number of interactions. B. What is the margin of error for the confidence interval you...
A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 126 students who averaged 34.8 texts per day. The standard deviation was 18.7 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a ? v distribution and texts. b. With 98% confidence the population mean number of texts per day is between c. If many groups of 126...
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 141 students who averaged 25.7 texts per day. The standard deviation was 21.2 texts. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a tv distribution. 0 and b. With 95% confidence the population mean number of texts per day is between texts. c. If many groups of 141...
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