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If 0.245 mol of H2SO4(g) reacts with excess NH3(g) at 75°C for the following reaction, 2NH3(g)...

If 0.245 mol of H2SO4(g) reacts with excess NH3(g) at 75°C for the following reaction,

2NH3(g) + H2SO4(g) → (NH4)2SO4(s)

what is the work done in terms of the system?

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