Question

The weight of cans of fruit is normally distributed with a mean (μ) of 300 grams and a standard deviation (σ) of 75 grams. What percent of the cans of fruit weigh less than 200 grams? Select one: a. 0.0026 b. 0.0100 c. 0.0918 d. 0.0968

Answer 1

Given that, mean (μ) = 300 grams and

standard deviation (σ) = 75 grams

We want to find, P(X < 200)

=> P(X < 200) = 0.0918

Answer : c) 0.0918

Answer 2

Given that, mean (μ) = 300 grams and

standard deviation (σ) = 75 grams

We want to find, P(X < 200)

=> P(X < 200) = 0.0918

Answer : c) 0.0918