A second order reaction where the starting reactant concentration is 0.0963 M has a measured rate constant of 0.70 M/s at 10 oC. What is the concentration of the reactant after 36.0 seconds?
- report your answer in three significant figures
- do not write your answer in scientific notation
- do not include units
The second order rate law is given by the equation:
1/[A]t - 1/[A]0 = kt
where [A]t and [A]0 are the concentrations of the reactant at time t and time zero, respectively, and k is the rate constant.
Rearranging the equation to solve for [A]t, we get:
[A]t = 1/([A]0 + kt[A]0)
Plugging in the given values, we have:
[A]t = 1/(0.0963 M + (0.70 M/s)(36.0 s)(0.0963 M))
[A]t = 0.042 M
Therefore, the concentration of the reactant after 36.0 seconds is 0.042 M.
A second order reaction where the starting reactant concentration is 0.0963 M has a measured rate...
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