Question

A diffraction grating with an unknown number of lines per mm, is illuminated by light at a wavelength l = 633 mm, and the first order diffraction pattern is seen at an angle

β= 45.O^O.

Light of a second wavelength is shone on to the grating, whose second order diffraction pattern is seen at l = 62.0⁰.

What is the wavelength of the second beam?

Answer 1

The equation of a diffraction grating is given by

here, m is the order of diffraction, lambda is the wavelength, d is the grating element and beta is the angle at which a particular order of diffraction is observed.

so, from the first part of the question we can calculate d as :

Now, we can use the second part of the question and put the value of d to calculate lambda of light as,

or Lambda= 395.20 mm

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