Question

I need a detailed pseudocode for this code in C ++. Thank you

#include <iostream>

#include <string>

#include <iomanip>

using namespace std;

struct Drink
{

   string name;

   double cost;

   int noOfDrinks;

};

void displayMenu(Drink drinks[], int n);

int main() {

   const int size = 5;
  
   Drink drinks[size] = { {"Cola", 0.65, 2},

   {"Root Beer", 0.70, 1},

   {"Grape Soda", 0.75, 5},

   {"Lemon-Lime", 0.85, 20},

   {"Water", 0.90, 20} };

   cout << setprecision(2) << fixed;

   int drink = -1;

   double amount, total_revenue = 0.0;

   displayMenu(drinks, size);

   while (drink <1 || drink > 6)
   {
       cout << "Invalid input. Please enter your choice again:";
       cin >> drink;
   }
   cout << "\nSelect a drink (1-5) or enter 6 to quit: ";

   cin >> drink;

   while (drink != 6) {
      

       cout << "Enter the amount of money you want to insert: ";

       cin >> amount;

       while (amount < 0 || amount > 1.00) {

           cout << "This machine cannot accept values less than 0 or greater than "

               "$1.00"

               << endl;

           cout << "Enter the amount of money you want to insert: ";

           cin >> amount;

       }

       if (amount < drinks[drink - 1].cost)

           cout << "Insufficient Funds" << endl;

       if (drinks[drink - 1].noOfDrinks == 0)

           cout << "SOLD OUT" << endl;

       else {

           drinks[drink - 1].noOfDrinks--;

           cout << "Change: $" << (amount - drinks[drink - 1].cost) << endl;

           total_revenue += drinks[drink - 1].cost;

       }

       displayMenu(drinks, size);

       cout << "\nSelect a drink (1-5) or enter 6 to quit: ";

       cin >> drink;

       }

       cout << "\nTotal Revenue: $" << total_revenue << endl;

       for (int i = 0; i < size; i++) {

           for (int j = i + 1; j < size; j++) {

               if (drinks[i].noOfDrinks > drinks[j].noOfDrinks) {

                   Drink temp = drinks[i];

                   drinks[i] = drinks[j];

                   drinks[j] = temp;

               }

           }

       }

       cout << "\nDrink\t\tNumber Left\n" << endl;

       for (int i = 0; i < size; i++) {

           cout << setw(15) << left << drinks[i].name << setw(2) << right << drinks[i].noOfDrinks << endl;

       }
  

   return 0;

}

void displayMenu(Drink drinks[], int n) {

   cout << endl;

   for (int i = 0; i < n; i++) {

       cout << (i + 1) << ") " << setw(15) << left << drinks[i].name << "$"

           << drinks[i].cost << "\t\t"

           << "Qty: " << setw(2) << right << drinks[i].noOfDrinks << endl;

   }

}

Answer 1

Hi there !

Happy to answer this question for you.

The above Program is in c++ and we need pseudo code for that.

Pseudo code is an informal way to write algorithmic procedure for any problem.Point here to note that pseudo code only includes the iterations (loops i.e while,for in c++),conditional statements (if/else and switch cases in c++) , sequence of statements ( like variable assignments,etc ) . Usually we do not write any particular statements for structure and classes.

define 'Drink' datatype with datatype fields string 'name',     floating point 'cost' 'noOfdrinks'

main() size <- 5 constant initialize array drink as drinks[size] = { {"Cola", 0.65, 2},{"Root Beer", 0.70, 1},{"Grape Soda", 0.75, 5},{"Lemon-Lime", 0.85, 20},{"Water", 0.90, 20}}; set the precision for floating point numbers to 2 drink <- -1 (note that everywhere <- shows arrow pointing to left ) amount,total_revenue <- 0.0

displayMenu(drinks,size)

while drinks is less than 1 or greater than 6 do print  "Invalid input. Please enter your choice again:" and take input the drink again from user end

print in a new line "Select a drink (1-5) or enter 6 to quit: " and take input the drink again from user

while drink not equal to 6 do print "Enter the amount of money you want to insert: " and take input the amount from user

while amount is less than 0 or greater than 1.00 do print "This machine cannot accept values less than 0 or greater than $1.00 " print "Enter the amount of money you want to insert: " and take input the amount again from user end    if amount is less than drinks[drink - 1].cost    print "Insufficient Funds"     if drinks[drink - 1].noOfDrinks <- 0 print "SOLD OUT"
       else drinks[drink - 1].noOfDrinks <- drinks[drink - 1].noOfDrinks - 1 //( decrease )           print "Change: $ " (amount - drinks[drink - 1].cost) << endl    total_revenue <-drinks[drink - 1].cost + total_revenue

       displayMenu(drinks, size)     print "Select a drink (1-5) or enter 6 to quit: " and take input drink from user end (end of outer while loop)

in a new line print "Total Revenue: $" print  total_revenue

for i <- 0 to size-1 do for j <- i + 1 size-1 do if drinks[i].noOfDrinks is greater than drinks[j].noOfDrinks    Drink temp <- drinks[i] drinks[i] <- drinks[j] drinks[j] <- temp end end   

in a new line print "Drink" with two tab    print "Number Left"

       for i <- 0 to size-1 do   

          print drinks[i].name left side with size width of 15     print drinks[i].noOfDrinks right side with width of 2

end

end (end of main function)

displayMenu ( Drink drinks[],n ) in a new line for i <- 0 to n-1 print i+1 with ")" print drinks[i].name on left side setting width of 15 with "$" print drinks[i].cost with two tab characters and string "Qty:" print drinks[i].noOfdrinks on the right setting width of two with end of line

You should note that in pseudo codes there is no need to mention the white space characters and setw methods.But you mentioned that you need detailed solution , that'ts why i wrote those characters to make you understand properly along with the code.

I hope that it is clear to you !

For any ambiguity and faultness please comment !

Thank you !